Space Station Lambda

Comments

1. Michael Klier
   July 9th, 2008 | 2:42 pm

   Nice articel! Here’s one in bash, doesn’t look as neat as the lisp solution though ;-) (I hope I get the formatting right).

   i=1
   for file in $(ls *.{png,jpg,jpeg,gif}); do 
     mv $file $(printf "pysolfc%s" $i).${file/*.} 
     i=$((i+1))
   done

2. dertyp
   July 9th, 2008 | 3:14 pm

   in python, it would probably look like this:

   #!/usr/bin/env python
    
   import re
   import os
    
   new_basename = 'pysolfc'
   a = 0
   for file_name in os.listdir(os.getcwd()):
           a += 1
           file_name_split = os.path.splitext(file_name)
           new_filename = (new_basename + str(a) + file_name_split[1])
           os.rename(file_name, b)

3. Mark Tran
   July 9th, 2008 | 4:40 pm

   ZSH

   i=1 zmv '*.(*)' 'pysolfc$((i++)).$1'

4. smoon
   July 9th, 2008 | 4:54 pm

   Assuming the order of the destination files does not matter, this works in sh and the like:

   for f in * ; do
       i=$(($i+1)) ; mv $f pysolfc$i.${f#*.}
   done

5. Michael Klier
   July 9th, 2008 | 5:19 pm

   @smoon, nice, after seeing your solution I am wondering what led me to use printf. Seems the first thing that came to my mind wasn’t the most obvious ;-).

6. codemac
   July 10th, 2008 | 1:25 am

   Yea, if you’re looking for the ultimate in renaming, you should check out zmv.

7. Michael Klier
   July 10th, 2008 | 10:36 am

   I haven’t done anything in perl in a while, but your post got me motivated ;-). So here’s a solution in perl:

   #!/usr/bin/env perl
   use warnings;
   use strict;
    
   my $i=1;
   foreach $_ (@ARGV) {
       if( $_ =~ /(jpeg|jpg|png|gif)/ ) {
           rename($_, "pysolfc" . $i++ . ".$1");
       }
   }

8. sandsmark
   July 10th, 2008 | 4:56 pm

   man rename

9. Brian
   July 11th, 2008 | 11:36 pm

   #!/usr/bin/ruby
    
   require 'fileutils'
    
   Dir.glob(ARGV[0]).each_with_index do |fn, i|
     FileUtils.mv(fn, File.join(File.dirname(fn), "pysol#{i+1}" + File.extname(fn)))
   end

10. one
    July 16th, 2008 | 2:59 pm

    i have a file, temp.txt in folder c:/TMP/Arch
    my script is in c:/script/script1.py

    i want to rename the file temp.txt with the date and time, but my script rename the file and then move the file in c:/script/

    can u tell me pls how to do ? i want the file with new name to remain in c:/TMP/Arch

    my script
    from time import time, localtime, strftime
    time_tuple = localtime(time())
    ddate = strftime(“%d.%m.%y-%H;%M;%S”, time_tuple)

    ext = “.txt”
    file = ‘c:/TMP/Arhiva/temp.txt’
    (basename,ext) = os.path.splitext(file)
    os.rename(file, ddate+ext)

11. Fredrik
    July 17th, 2008 | 11:14 pm

    Python:

    from os import listdir, rename, path
     
    for i, name in enumerate(listdir(".")):
        rename(name, "pysolfc%d%s" % (i+1, path.splitext(name)[1]))

    or, a bit too clever perhaps:

    from os import listdir, rename, path
     
    any(rename(name, "pysolfc%d%s" % (i+1, path.splitext(name)[1]))
        for i, name in enumerate(listdir(".")))

    Python’s penalized by explicit import of subsystems (the number of “built-ins” is relatively small), and less powerful formatting. But three lines are three lines… ;-)

12. Marco
    July 26th, 2008 | 5:15 pm

    Just a small issue with the python example, if run as a script it will rename itself.

13. Leslie
    July 27th, 2008 | 9:34 am

    How cute, it’s self-modifying code.

14. omid8bimo
    February 27th, 2010 | 6:12 pm

    cool pieces of codes

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